ȯ±â·®À» ±¸ÇÏ´Â ½ÄÀº ´ÙÀ½°ú °°½À´Ï´Ù:
[ \text{ÇÊ¿ä ȯ±â·®} (m^3/h) = \text{°ø°£ ºÎÇÇ} (m^3) \times \text{ȯ±âȽ¼ö} (/h) ]
ÁÖ¾îÁø Á¤º¸¿¡ µû¸£¸é °ø°£ÀÇ ¸éÀûÀÌ 50ÆòÀÌ°í, õÁ¤ÀÇ ³ôÀÌ°¡ 2.4mÀÔ´Ï´Ù. ¸ÕÀú Æò¼ö¸¦ Á¦°ö¹ÌÅÍ·Î º¯È¯ÇØ¾ß ÇÕ´Ï´Ù. ÇÑ ÆòÀº ´ë·« 3.3058Á¦°ö¹ÌÅÍÀÔ´Ï´Ù. µû¶ó¼,
[ 50Æò = 50 \times 3.3058 = 165.29 m^2 ]
ÀÌÁ¦ °ø°£ÀÇ ºÎÇǸ¦ ±¸ÇÒ ¼ö ÀÖ½À´Ï´Ù:
[ °ø°£ÀÇ ºÎÇÇ = ¸éÀû \times ³ôÀÌ = 165.29 m^2 \times 2.4m = 396.696 m^3 ]
¸¶Áö¸·À¸·Î ÇÊ¿ä ȯ±â·®Àº:
[ ÇÊ¿ä ȯ±â·® = 396.696 m^3 \times 2.5 = 991.74 m^3/h ]
µû¶ó¼, ÇØ´ç ÁöÇÏ °ø°£ÀÇ ÇÊ¿ä ȯ±â·®Àº ¾à 991.74 m^3/h ÀÔ´Ï´Ù.