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rank ¾ÆÇ϶ó7 2018-10-06 (Åä) 17:35 Á¶È¸ : 452

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2. A colleague of yours has suggested a new way to measure the variability (or ¡°spread-outness¡±) of the data you are studying. They suggest the following formula for the data values you are studying. They also state that you add every other data value, and every other¡±error¡°in the numerator.

In case you have 8 data values, for example, they suggest you proceed as follows:

   x 1 + ( x 2 − x ) + x 3 + ( x 4 − x ) + x 5 + ( x 6 − x ) + x 7 + ( x 8 − x )

d =

8

a What might cause issues with this approach? b How does this compare with the M.A.D.?

Regression and Estimation

3. A colleague decides that they would like to use a regression model to predict a variable, Y , as a response to a variable, X

q2.png


a.                       For a value of x = 7, what would you predict as the corresponding y value?

b.                      For a value of x = 9, what would you predict as the corresponding y value?

c.                       For the y value you found in a. above, give an estimate of the likely range or variability in the possible values of y that we might observe.

d.                      Does this model give a good prediction of y in response to x ? Why or why not?

4. A regression model is built to predict the pH pf well water from Bicarbonate content in p.p.m. After performing the work in Excel, the following results are obtained:

q3.png


Coefficients

Intercept 432.15 Slope -37.78

a.      At a pH of 7.3, what is the estimated Bicarb in p.p.m.?

b.     Is this scatterplot reflective of a strong relationship between pH and Bicarb? Why or why not?

c.      Is it fair to say the Intercept of 432.15 is reflective of the Bicarb at a pH of 0? If so why? If not, why not?

d.     Consider the putput given below: Regression Statistics

R Square 0.115

Observations 34

Is y = 37 . 78 + 432 . 15 a good prediction model for Bicarb in p.p.m. as a response to pH? Why or Why not?

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ranklemo 2018-10-06 (Åä) 20:01
2.

10 ÀÌ ±âÁØÀ̸é

[(12 - 10) + (8 - 10)]/2 == [(10 - 10) + (10 - 10)]/2

À¸·Î ÁÂ¿ì µÑ ´Ù 0 ÀÌ µË´Ï´Ù.

ÇÏÁö¸¸ 'Â÷ÀÌÀÇ Àý´ë°ª'À¸·Î ³ªÅ¸³»¸é

[2 + 2]/2  == 2

[0 + 0]/2 == 0

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